Homeownership Rate in Wakulla County, FL
ACS 2024 5-Year Estimates
How Wakulla County Compares
National Distribution
Where Wakulla County falls among all 3,222 U.S. counties for homeownership rate.
■ Wakulla County: 81.9%
Ranking Context
| Rank | County | Value |
|---|---|---|
| #375 | Price County, WI | 81.9% |
| #376 | Waldo County, ME | 81.9% |
| #377 | Valley County, ID | 81.9% |
| #378 | Wakulla County, FL | 81.9% |
| #379 | Boone County, NE | 81.9% |
| #380 | Traverse County, MN | 81.8% |
| #381 | Mason County, WV | 81.8% |
Homeownership Rate in Wakulla County, Florida
Wakulla County, Florida has a homeownership rate of 81.9%, which ranks #378 of 3,222 out of 3,222 counties nationwide. This is 27.1% above the national value of 64.4%.
Within Florida, Wakulla County ranks #12 of 67 out of 67 counties. This places it in the 88th percentile nationally.
Percentage of occupied housing units that are owner-occupied. All data comes from the U.S. Census Bureau's American Community Survey (ACS) 5-Year Estimates for 2024.
About this data
Source: U.S. Census Bureau, American Community Survey 5-Year Estimates (2024). All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.