Health Insurance Coverage in Wakulla County, FL
ACS 2024 5-Year Estimates
How Wakulla County Compares
National Distribution
Where Wakulla County falls among all 3,222 U.S. counties for health insurance coverage.
■ Wakulla County: 93.2%
Ranking Context
| Rank | County | Value |
|---|---|---|
| #1,329 | Marion County, KS | 93.2% |
| #1,330 | Greene County, VA | 93.2% |
| #1,331 | Harris County, GA | 93.2% |
| #1,332 | Wakulla County, FL | 93.2% |
| #1,333 | Wayne County, NY | 93.2% |
| #1,334 | Mingo County, WV | 93.2% |
| #1,335 | Phillips County, CO | 93.2% |
Health Insurance Coverage in Wakulla County, Florida
Wakulla County, Florida has a health insurance coverage of 93.2%, which ranks #1,332 of 3,222 out of 3,222 counties nationwide. This is 1.6% above the national value of 91.7%.
Within Florida, Wakulla County ranks #3 of 67 out of 67 counties. This places it in the 59th percentile nationally.
Percentage of the population with health insurance coverage. All data comes from the U.S. Census Bureau's American Community Survey (ACS) 5-Year Estimates for 2024.
About this data
Source: U.S. Census Bureau, American Community Survey 5-Year Estimates (2024). All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.