Health Insurance Coverage in Switzerland County, IN

ACS 2024 5-Year Estimates

Health Insurance Coverage
87.0% −5.1% vs nat'l
Rank #2,694 of 3,222
16th percentile

How Switzerland County Compares

Switzerland County
87.0%
Indiana Average
87.0%
Rank #87 of 92 in state
National
91.7%
5.1% below

National Distribution

Where Switzerland County falls among all 3,222 U.S. counties for health insurance coverage.

55.4% 100.0%

■ Switzerland County: 87.0%

Ranking Context

Rank County Value
#2,691 Oscoda County, MI 87.0%
#2,692 Holmes County, FL 87.0%
#2,693 Jackson County, OK 87.0%
#2,694 Switzerland County, IN 87.0%
#2,695 Butler County, MO 87.0%
#2,696 Okmulgee County, OK 87.0%
#2,697 Casey County, KY 87.0%
View full ranking →

Health Insurance Coverage in Switzerland County, Indiana

Switzerland County, Indiana has a health insurance coverage of 87.0%, which ranks #2,694 of 3,222 out of 3,222 counties nationwide. This is 5.1% below the national value of 91.7%.

Within Indiana, Switzerland County ranks #87 of 92 out of 92 counties. This places it in the 16th percentile nationally.

Percentage of the population with health insurance coverage. All data comes from the U.S. Census Bureau's American Community Survey (ACS) 5-Year Estimates for 2024.

About this data

Source: U.S. Census Bureau, American Community Survey 5-Year Estimates (2024). All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.