Health Insurance Coverage in Seneca County, OH

ACS 2024 5-Year Estimates

Health Insurance Coverage
94.7% +3.3% vs nat'l
Rank #761 of 3,222
76th percentile

How Seneca County Compares

Seneca County
94.7%
Ohio Average
94.7%
Rank #27 of 88 in state
National
91.7%
3.3% above

National Distribution

Where Seneca County falls among all 3,222 U.S. counties for health insurance coverage.

55.4% 100.0%

■ Seneca County: 94.7%

Ranking Context

Rank County Value
#758 Monmouth County, NJ 94.7%
#759 Polk County, IA 94.7%
#760 Bayfield County, WI 94.7%
#761 Seneca County, OH 94.7%
#762 Cumberland County, IL 94.7%
#763 Kane County, UT 94.7%
#764 McCone County, MT 94.7%
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Health Insurance Coverage in Seneca County, Ohio

Seneca County, Ohio has a health insurance coverage of 94.7%, which ranks #761 of 3,222 out of 3,222 counties nationwide. This is 3.3% above the national value of 91.7%.

Within Ohio, Seneca County ranks #27 of 88 out of 88 counties. This places it in the 76th percentile nationally.

Percentage of the population with health insurance coverage. All data comes from the U.S. Census Bureau's American Community Survey (ACS) 5-Year Estimates for 2024.

About this data

Source: U.S. Census Bureau, American Community Survey 5-Year Estimates (2024). All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.