Health Insurance Coverage in Sandusky County, OH
ACS 2024 5-Year Estimates
How Sandusky County Compares
National Distribution
Where Sandusky County falls among all 3,222 U.S. counties for health insurance coverage.
■ Sandusky County: 93.7%
Ranking Context
| Rank | County | Value |
|---|---|---|
| #1,142 | San Joaquin County, CA | 93.7% |
| #1,143 | Emmons County, ND | 93.7% |
| #1,144 | Sheridan County, ND | 93.7% |
| #1,145 | Sandusky County, OH | 93.7% |
| #1,146 | Henry County, VA | 93.7% |
| #1,147 | Codington County, SD | 93.7% |
| #1,148 | Pickett County, TN | 93.7% |
Health Insurance Coverage in Sandusky County, Ohio
Sandusky County, Ohio has a health insurance coverage of 93.7%, which ranks #1,145 of 3,222 out of 3,222 counties nationwide. This is 2.2% above the national value of 91.7%.
Within Ohio, Sandusky County ranks #50 of 88 out of 88 counties. This places it in the 64th percentile nationally.
Percentage of the population with health insurance coverage. All data comes from the U.S. Census Bureau's American Community Survey (ACS) 5-Year Estimates for 2024.
About this data
Source: U.S. Census Bureau, American Community Survey 5-Year Estimates (2024). All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.