Health Insurance Coverage in Osceola County, FL

ACS 2024 5-Year Estimates

Health Insurance Coverage
89.4% −2.5% vs nat'l
Rank #2,296 of 3,222
29th percentile

How Osceola County Compares

Osceola County
89.4%
Florida Average
89.4%
Rank #27 of 67 in state
National
91.7%
2.5% below

National Distribution

Where Osceola County falls among all 3,222 U.S. counties for health insurance coverage.

55.4% 100.0%

■ Osceola County: 89.4%

Ranking Context

Rank County Value
#2,293 Fremont County, ID 89.4%
#2,294 Monroe County, MO 89.4%
#2,295 Coryell County, TX 89.4%
#2,296 Osceola County, FL 89.4%
#2,297 Walworth County, SD 89.4%
#2,298 Rockingham County, VA 89.4%
#2,299 Morton County, KS 89.4%
View full ranking →

Health Insurance Coverage in Osceola County, Florida

Osceola County, Florida has a health insurance coverage of 89.4%, which ranks #2,296 of 3,222 out of 3,222 counties nationwide. This is 2.5% below the national value of 91.7%.

Within Florida, Osceola County ranks #27 of 67 out of 67 counties. This places it in the 29th percentile nationally.

Percentage of the population with health insurance coverage. All data comes from the U.S. Census Bureau's American Community Survey (ACS) 5-Year Estimates for 2024.

About this data

Source: U.S. Census Bureau, American Community Survey 5-Year Estimates (2024). All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.