Health Insurance Coverage in Medina County, OH
ACS 2024 5-Year Estimates
How Medina County Compares
National Distribution
Where Medina County falls among all 3,222 U.S. counties for health insurance coverage.
■ Medina County: 96.0%
Ranking Context
| Rank | County | Value |
|---|---|---|
| #288 | Columbia County, PA | 96.0% |
| #289 | Caledonia County, VT | 96.0% |
| #290 | Van Wert County, OH | 96.0% |
| #291 | Medina County, OH | 96.0% |
| #292 | Kendall County, IL | 96.0% |
| #293 | Robertson County, KY | 96.0% |
| #294 | Douglas County, MN | 96.0% |
Health Insurance Coverage in Medina County, Ohio
Medina County, Ohio has a health insurance coverage of 96.0%, which ranks #291 of 3,222 out of 3,222 counties nationwide. This is 4.7% above the national value of 91.7%.
Within Ohio, Medina County ranks #9 of 88 out of 88 counties. This places it in the 91th percentile nationally.
Percentage of the population with health insurance coverage. All data comes from the U.S. Census Bureau's American Community Survey (ACS) 5-Year Estimates for 2024.
About this data
Source: U.S. Census Bureau, American Community Survey 5-Year Estimates (2024). All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.