Health Insurance Coverage in Allen County, OH
ACS 2024 5-Year Estimates
How Allen County Compares
National Distribution
Where Allen County falls among all 3,222 U.S. counties for health insurance coverage.
■ Allen County: 94.1%
Ranking Context
| Rank | County | Value |
|---|---|---|
| #1,006 | Cheboygan County, MI | 94.1% |
| #1,007 | Fairfield County, OH | 94.1% |
| #1,008 | Cottonwood County, MN | 94.1% |
| #1,009 | Allen County, OH | 94.1% |
| #1,010 | New Castle County, DE | 94.1% |
| #1,011 | Berkeley County, WV | 94.1% |
| #1,012 | Belknap County, NH | 94.1% |
Health Insurance Coverage in Allen County, Ohio
Allen County, Ohio has a health insurance coverage of 94.1%, which ranks #1,009 of 3,222 out of 3,222 counties nationwide. This is 2.6% above the national value of 91.7%.
Within Ohio, Allen County ranks #44 of 88 out of 88 counties. This places it in the 69th percentile nationally.
Percentage of the population with health insurance coverage. All data comes from the U.S. Census Bureau's American Community Survey (ACS) 5-Year Estimates for 2024.
About this data
Source: U.S. Census Bureau, American Community Survey 5-Year Estimates (2024). All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.